(6/(5x))-(1/(x+1))=(1/(2x^2+2x))

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Solution for (6/(5x))-(1/(x+1))=(1/(2x^2+2x)) equation:


D( x )

2*x^2+2*x = 0

x+1 = 0

5*x = 0

2*x^2+2*x = 0

2*x^2+2*x = 0

2*x^2+2*x = 0

DELTA = 2^2-(0*2*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-2)/(2*2) or x = (-4^(1/2)-2)/(2*2)

x = 0 or x = -1

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:-1) U (-1:0) U (0:+oo)

6/(5*x)-(1/(x+1)) = 1/(2*x^2+2*x) // - 1/(2*x^2+2*x)

6/(5*x)-(1/(x+1))-(1/(2*x^2+2*x)) = 0

6/(5*x)-(x+1)^-1-(2*x^2+2*x)^-1 = 0

6/(5*x)-1/(x+1)-1/(2*x^2+2*x) = 0

2*x^2+2*x = 0

2*x^2+2*x = 0

2*x*(x+1) = 0

x+1 = 0 // - 1

x = -1

2*x*(x+1) = 0

6/(5*x)-1/(x+1)-1/(2*x*(x+1)) = 0

(-1*2*5*x*x)/(2*5*x*x*(x+1))+(-1*5*x)/(2*5*x*x*(x+1))+(2*6*x*(x+1))/(2*5*x*x*(x+1)) = 0

2*6*x*(x+1)-1*2*5*x*x-1*5*x = 0

12*x^2-10*x^2-5*x+12*x = 0

2*x^2+7*x = 0

2*x^2+7*x = 0

x*(2*x+7) = 0

2*x+7 = 0 // - 7

2*x = -7 // : 2

x = -7/2

x*(x+7/2) = 0

(x*(x+7/2))/(2*5*x*x*(x+1)) = 0

(x*(x+7/2))/(2*5*x*x*(x+1)) = 0 // * 2*5*x*x*(x+1)

x*(x+7/2) = 0

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

( x )

x = 0

x in { 0}

x = -7/2

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